hdu1029——Ignatius and the Princess IV-白红宇

hdu1029——Ignatius and the Princess IV

阅读量：2344 次

发布时间：2019-05-10

本文共 1514 字，大约阅读时间需要 5 分钟。

Problem Description

“OK, you are not too bad, em… But you can never pass the next test.” feng5166 says.

“I will tell you an odd number N, and then N integers. There will be a special integer among them, you have to tell me which integer is the special one after I tell you all the integers.” feng5166 says.

“But what is the characteristic of the special integer?” Ignatius asks.

“The integer will appear at least (N+1)/2 times. If you can’t find the right integer, I will kill the Princess, and you will be my dinner, too. Hahahaha…..” feng5166 says.

Can you find the special integer for Ignatius?

Input

The input contains several test cases. Each test case contains two lines. The first line consists of an odd integer N(1<=N<=999999) which indicate the number of the integers feng5166 will tell our hero. The second line contains the N integers. The input is terminated by the end of file.

Output

For each test case, you have to output only one line which contains the special number you have found.

Sample Input

1 3 2 3 3

1 1 1 1 1 5 5 5 5 5 5

1 1 1 1 1 1 1

Sample Output

题意是求序列中超过总个数一半的那个数是多少

正确的思路应该是：在原序列中，减去两个不同的数，剩下的序列中多一半的还是那个数。有一个0(n)的算法

但。。。。n的数据范围不大，可以直接暴力

#include 
   
    #include 
    
     #include 
     
      #include 
      
       #include 
       
        #include 
        
         #include 
         
          #include 
          
           #include 
           #include 
            
             #define INF 0x3f3f3f3f#define MAXN 110000#define Mod 10001using namespace std;int a[1000009];int main(){ int n,m,ans; while(~scanf("%d",&n)) { memset(a,0,sizeof(a)); for(int i=0;i

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